x^2-0.9x+0.06=0

Solution for x^2-0.9x+0.06=0 equation:

x^2-0.9x+0.06=0

a = 1; b = -0.9; c = +0.06;
Δ = b2-4ac
Δ = -0.92-4·1·0.06
Δ = 0.57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.9)-\sqrt{0.57}}{2*1}=\frac{0.9-\sqrt{0.57}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.9)+\sqrt{0.57}}{2*1}=\frac{0.9+\sqrt{0.57}}{2}
$